(4x^5+3x-12)-(3x^3+x^2-3x-7)=0

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Solution for (4x^5+3x-12)-(3x^3+x^2-3x-7)=0 equation: 


Simplifying
(4x5 + 3x + -12) + -1(3x3 + x2 + -3x + -7) = 0

Reorder the terms:
(-12 + 3x + 4x5) + -1(3x3 + x2 + -3x + -7) = 0

Remove parenthesis around (-12 + 3x + 4x5)
-12 + 3x + 4x5 + -1(3x3 + x2 + -3x + -7) = 0

Reorder the terms:
-12 + 3x + 4x5 + -1(-7 + -3x + x2 + 3x3) = 0
-12 + 3x + 4x5 + (-7 * -1 + -3x * -1 + x2 * -1 + 3x3 * -1) = 0
-12 + 3x + 4x5 + (7 + 3x + -1x2 + -3x3) = 0

Reorder the terms:
-12 + 7 + 3x + 3x + -1x2 + -3x3 + 4x5 = 0

Combine like terms: -12 + 7 = -5
-5 + 3x + 3x + -1x2 + -3x3 + 4x5 = 0

Combine like terms: 3x + 3x = 6x
-5 + 6x + -1x2 + -3x3 + 4x5 = 0

Solving
-5 + 6x + -1x2 + -3x3 + 4x5 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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